I am having real trouble understanding this concept and I am hoping that maybe someone would be willing to help me out.
I need to find the equation for a plane that just touches the sphere (x - 2)^2 + (y - 3)^2 = (z - 3)^2 = 16 and is parallel to 1) xy plane 2) yz plane and 3) the xz plane. If someone can walk me through one of these I should be able to apply the info to the other two. Thanks very much!!!
Also, if the function (x,y,z) = x^2 + y^2 + z^2 - 2x + 3y + z I need to find a point (a,b,c) such that the function can be expressed in terms of distance from (a,b,c)
I know I need to complete the square but I am lost........
Can someone recommend a good online 3D graphing program? I need to really work on understanding what different equations look like in 3D. Thanks again, this site is WONDERFUL!
The sphere has centre (2,3,3) and radius 4. So at its highest point z will be 3+4, and at its lowest point z will be 3–4. There are therefore two planes parallel to the x-y plane that touch the sphere, namely and .