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Math Help - Very strange? Limit inferiror of a sequence of functions.

  1. #1
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    Very strange? Limit inferiror of a sequence of functions.

    If there were a countable sequence of functions fn(x), eg f1(x), f2 (x), .......
    what is the infimum limit (lim inf) of the set of funtions, is it the pointwise convergence function, ie lim inf for every value of x?
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    Take an example:
    \left\{\frac{(x-2)^n}{5^n(3n+2)}\right\}_{n=1}^{\infty}
    That is a sequence:
    \left\{a_n(x-a)^n\right\}_{n=1}^{\infty}
    I can find a limit superior of a_n:
    \limsup_{n\to\infty}\frac{1}{5^n(3n+2)}=0
    and also limit inferior:
    \liminf_{n\to\infty}\frac{1}{5^n(3n+2)}=0
    This sequence is convergent because
    \limsup_{n\to\infty}a_n=\liminf_{n\to\infty}a_n=\l  im_{n\to\infty}a_n
    The sequence
    \left\{\frac{(x-2)^n}{5^n(3n+2)}\right\}_{n=1}^{\infty}
    is convergent only for some x. You have to find the radius of convergence by the limit:
    r:=\limsup_{n\to\infty}\frac{1}{\sqrt[n]{|a_n|}}
    if r\in\mathbb{R}, then radius R is:
    R=\frac{1}{r}
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  3. #3
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    Quote Originally Posted by danirouge View Post
    If there were a countable sequence of functions fn(x), eg f1(x), f2 (x), .......
    what is the infimum limit (lim inf) of the set of funtions, is it the pointwise convergence function, ie lim inf for every value of x?
    Yes.
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