Hello,
What is the method of integrating I = (x + 1)/(2x + 3)?
I get a wrong answer: 0.5x - 0.5ln(2x + 3)
The correct answer is 0.5x - 0.25ln(2x + 3)
My method:
Let (x+1) = A{2x + 3} + B{differential coefficient of 2x + 3}
(x+1) = A{2x + 3} + B{2}
equating coefficient of x: 1 = 2A :. A = 0.5
constants: 1 = 3A + B :. B = -0.5
:. I = 0.5x - 0.5ln(2x + 3)
Thank you