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Math Help - integration question

  1. #1
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    integration question

    y=\frac{4}{x^2}

    why is this

    y=\frac{4x}{x^3}

    and not

    y=\frac{4x}{0.3333x^3}


    sorry i dont know hwo to do a fraction in a fraction so 0.33333 = one third
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  2. #2
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    Quote Originally Posted by coyoteflare View Post
    y=\frac{4}{x^2}

    why is this

    y=\frac{4x}{x^3}

    and not

    y=\frac{4x}{0.3333x^3}


    sorry i dont know hwo to do a fraction in a fraction so 0.33333 = one third
    Are you trying to integrate \frac{4}{x^2} i.e.

    \int \frac{4}{x^2}\, dx?
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  3. #3
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    Quote Originally Posted by danny arrigo View Post
    Are you trying to integrate \frac{4}{x^2} i.e.

    \int \frac{4}{x^2}\, dx?
    heres the question

    A is the point (2,1) on the curve y=\frac{4}{x^2}

    use calculas to find the gradient of the curve at A
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  4. #4
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    Quote Originally Posted by coyoteflare View Post
    heres the question

    A is the point (2,1) on the curve y=\frac{4}{x^2}

    use calculas to find the gradient of the curve at A
    Oh, you want the slope of the tangent. In this case you'll need the derivative. So

    \frac{d}{dx} \left( \frac{4}{x^2} \right) = \frac{d}{dx} \left( 4 x^{-2} \right)

    Once you have this, evaluate it at x = 2 and you'll have your answer.
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