can please someone show me the derivative of this using chain rule without simplifying y=^1/2 sin (x+x^1/2)^1/2 cot x^1/2 thanks
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Originally Posted by maeca can please someone show me the derivative of this using chain rule without simplifying y=^1/2 sin (x+x^1/2)^1/2 cot x^1/2 thanks Is that $\displaystyle y = \frac{1}{2} \sin{(x + x^{\frac{1}{2}})^{\frac{1}{2}}} \cot{x^{\frac{1}{2}}}$?
sorry. it's y=x^1/2 sin (x+x^1/2)^1/2 cot x^1/2
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