Thread: Calculus: Integral of (x)/(1+4x^2) dx?

Hello,

Originally Posted by serendipituous

I have a couple of problems that look a lot like this in my homework. It looks like an inverse tangent but I dont know how to approach it b.c there is the x in the numerator. Any help is much appreciated!

Just substitute t=1+4x²
And note that dt=8x dx ---> dx=dt/(8x)
so the x will be cancelled out