Hi,
Q1. Find the derivative of y=(3x-2)e^-x
steps and answers would be appreciated,
thanks,
moon
Hello,
Note that the derivative of e^(-x) is -e^(-x) (applying the chain rule).
Now use the product rule to find the derivative :
$\displaystyle [uv]'=u'v+uv'$
> $\displaystyle =(3x-2)' e^{-x}+(3x-2) (e^{-x})'=(3) e^{-x}+(3x-2) (-e^{-x})$
$\displaystyle =e^{-x} \left(3-(3x-2)\right)=e^{-x}(-3x+5)$