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    calc help

    Make a substitution to express the integrand as a rational function and then evaluate the integral.
    integral from 16 to 9 of (square root x)/ (x-4) dx (Let u= square root of x.)
    Thanks
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  2. #2
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    Quote Originally Posted by twilightstr View Post
    Make a substitution to express the integrand as a rational function and then evaluate the integral.
    integral from 16 to 9 of (square root x)/ (x-4) dx (Let u= square root of x.)
    Thanks
    \int_9^{16} \frac{\sqrt{x}}{x-4}\,dx
    If u = \sqrt{x} then du = \frac{dx}{2\sqrt{x}} or 2 u du = dx

    So (remember - change your limits of integration)

    \int_9^{16} \frac{\sqrt{x}}{x-4}\,dx = \int_3^4 \frac{2u^2}{u^2-4}\, du. Can you take it from here?
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