Differentiate $\displaystyle y= \frac{1}{\sqrt{1-x}}$ with respect to $\displaystyle x$. Is this correct, used chain rule: $\displaystyle \frac{\mathrm{d}y}{\mathrm{d}x} = \frac12\left(1-x\right)^{-\frac32}$?
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Hello Originally Posted by Air Differentiate $\displaystyle y= \frac{1}{\sqrt{1-x}}$ with respect to $\displaystyle x$. Is this correct, used chain rule: $\displaystyle \frac{\mathrm{d}y}{\mathrm{d}x} = \frac12\left(1-x\right)^{-\frac32}$? Yes it is correct.
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