# Thread: Indefinite Integral question 2

1. ## Indefinite Integral question 2

integral(3t^(5)-t^(5/3))dt=?
Thanks for the help.

2. For this you just apply the basic intergration rules, raise the power and then divide the coffeficiant of $\displaystyle t$ by the new power.

$\displaystyle \int3t^5-t^\frac{5}{3} dt = \frac{3}{6}t^6-\frac{3}{8}t^\frac{8}{3} + C$.

Have you attempted questions like these before?

3. Originally Posted by craig
For this you just apply the basic intergration rules, raise the power and then divide the coffeficiant of $\displaystyle t$ by the new power.

$\displaystyle \int3t^5-t^\frac{5}{3} dt = \frac{3}{6}t^6-\frac{3}{8}t^\frac{8}{3}$.

Have you attempted questions like these before?
Well, $\displaystyle \int3t^5-t^\frac{5}{3} dt = \frac{3}{6}t^6-\frac{3}{8}t^\frac{8}{3}+ C$.

4. Originally Posted by HallsofIvy
Well, $\displaystyle \int3t^5-t^\frac{5}{3} dt = \frac{3}{6}t^6-\frac{3}{8}t^\frac{8}{3}+ C$.
Thanks for spotting that, As hard as I try I can never remember the plus C