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Math Help - Indefinite Integral question 2

  1. #1
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    Indefinite Integral question 2

    integral(3t^(5)-t^(5/3))dt=?
    Thanks for the help.
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  2. #2
    Super Member craig's Avatar
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    For this you just apply the basic intergration rules, raise the power and then divide the coffeficiant of t by the new power.

    \int3t^5-t^\frac{5}{3} dt = \frac{3}{6}t^6-\frac{3}{8}t^\frac{8}{3} + C.

    Have you attempted questions like these before?
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  3. #3
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    Quote Originally Posted by craig View Post
    For this you just apply the basic intergration rules, raise the power and then divide the coffeficiant of t by the new power.

    \int3t^5-t^\frac{5}{3} dt = \frac{3}{6}t^6-\frac{3}{8}t^\frac{8}{3}.

    Have you attempted questions like these before?
    Well, \int3t^5-t^\frac{5}{3} dt = \frac{3}{6}t^6-\frac{3}{8}t^\frac{8}{3}+ C.
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  4. #4
    Super Member craig's Avatar
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    Quote Originally Posted by HallsofIvy View Post
    Well, \int3t^5-t^\frac{5}{3} dt = \frac{3}{6}t^6-\frac{3}{8}t^\frac{8}{3}+ C.
    Thanks for spotting that, As hard as I try I can never remember the plus C
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