1.) xy dx + e^(-x^2)dy=0 ; y(o)=1
i got that problem down to 1/2 e^(-x^2) = 1/2(y^2) - lny
but i don't know how to solve that for y
Last edited by holly123; Jan 8th 2009 at 02:10 PM.
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oh im sorry i wrote it wrong! it's
xy dx + e^(-x^2) (y^2-1) dy=0
sorry im confused on how to use the symbols and write this all out correctly and i completely forgot to add the (y^2 -1)
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