Originally Posted by

**Moon Hoplite** hi,

Q1.

f(x)=(x-2)(x+1)^2

a) find the min and max values of f(x):

b) A point of inflection is a point where the graph changes direction of concavity, i.e. a point where f''(x)=0. Find the inflection point(s) of f, and determine where the function is concave up and concave down.

ok..

for a),

i presumed that if y'=0 then it is either the min/max value,

so using product rule, i got 0=2(x+1)(x-2)

i.e. x=-1 or x=2

so with those x values, the function will be at its min = 0,

i also presumed that the max value is infinity...

for b), well im stuck on that

could anyone help me on both questions?

thanks,

moon