Hi,
Q1. find equation of the tangent line and the normal line to the curve
y=(3x-2)e^-x at the point (0,-2).
Q2. Find derivative of cos(x+y) + y = 0
thanks,
moon
Hi,
Q1. find equation of the tangent line and the normal line to the curve
y=(3x-2)e^-x at the point (0,-2).
Q2. Find derivative of cos(x+y) + y = 0
thanks,
moon
to Q1:
1, Use product and chain rule to calculate the first derivative ( )
2. Plug in x = 0 to get the slope of the tangent (m = 5)
3. Use point-slope-formula of the straight line to get the equation of the tangent (y+2=5(x-0) )
4. Calculate the negative reciprocal of m to get the slope of the normal to the curve in (0, -2): ( )
5. Use point-slope-formula to get the equation of the normal: ( )
6. Now it's your turn!