1. Another differentiable Equation question

ax^2 + 1/3, x> 1
f(x)=
bx -10/3, x<1

If the function is differentiable, find the sum of a + b

I got that a+ 1/3 = b - 10/3

Where do I go from there?

2. you did the f(x) is continuous part ...

need to do this, too, to get the second equation.

$\lim_{x \to 1^-} f'(x) = \lim_{x \to 1^+} f'(x)$

3. Ok, then I get 2a = b, so do I plug that back in to the original equations that were set equal to one another?

EDIT:

I ended up getting 11

4. Originally Posted by CalcGeek31
Ok, then I get 2a = b, so do I plug that back in to the original equations that were set equal to one another?

EDIT:

I ended up getting 11 Mr F says: Correct.
For the record: Now you solve the following equations simultaneously for a and b:

$a + \frac{1}{3} = b - \frac{10}{3}$ .... (1)

$2a = b$ .... (2)

Then you calculate the value of a + b.

You get what you got.