I know this is simple but I can't remember how to do this at all! Just going over antiderivatives...
Starting speed = 55mph (straight road)
Constant deceleration = 11ft/s^2
How do I work out the stopping distance?
Thanks for any help!!
I know this is simple but I can't remember how to do this at all! Just going over antiderivatives...
Starting speed = 55mph (straight road)
Constant deceleration = 11ft/s^2
How do I work out the stopping distance?
Thanks for any help!!
convert $\displaystyle v_0 = 55 \, mph$ to $\displaystyle ft/sec$
$\displaystyle v(t) = v_0 - 11t$
calculate the amount of time it takes to stop ... $\displaystyle t_s$
stopping distance = $\displaystyle \int_0^{t_s} v(t) \, dt$
note that the stopping distance is very easy to calculate with a velocity graph.