well i have some problems i have tried hard to solve them but wasnt succeed
1- find the equation of the plane throw (2,-1,3) , (-3,4,3) and parallel to the vector <-5,-3,2>
2- find the distance between the two planes 4x-3y+2z-9=0 .
8x-6y+4z=0
3-find the equation of the plane through (1,2,3) and perpendicular to
3x-y+2z+5=0 , 4x+2y-3z+8=0
help plz my exams is next week
The equations of both planes are in normal form. They are parallel because
The second plane passes through the origin. You only have to calculate the distance of the origin to the first plane:
Re-write the first equation in Hesse normal form, that means divide the equation by
Then the distance of the origin to the first plane is