Consider the curve defined by $\displaystyle -8x^2+5xy+y^3=-149$

I know that dy/dx = (16x-5y)/(5x+3y^2)

I also know that the equation of the line tangent to the curve at point (4,-1) is y+1=3(x-4).

However, now I'm asked the following..

1. There's a number k so that the point (4.2,k) is on the curve. Using the tangent line, approximate the value of k.

2. Write an equation that can be solved to find the actual value of k so that point (4.2,k) is on the curve.

3. Solve the equation found in part (d) for the actual value of k.

I don't even know where to BEGIN. I'm not looking for the answer, I'm looking for someone patient enough to teach me and guide me to the solution.

Please help, thanks.