$\displaystyle \int_{0}^{2} t^2sin{t^3} + 2.5dt$

So I started with integration by parts.

$\displaystyle \int_{0}^{2} t^2sint^3dt + \int_{0}^{2} 2.5dt $

$\displaystyle u = t^2 $

$\displaystyle du = 2tdt $

$\displaystyle dv = sint^3dt$

$\displaystyle v = \frac{-1}{3t^2}cos(t^3) $

but then I realized this was gonna go on for a long time. Is there an easier way to take this integral?