Temperature

Quote:

The initial temperature at midnight T(0) was -15F and at noon, T(12) was 5F. Find a and b.

$T(h) = -a - b\cos\left(\frac{\pi h}{12}\right)$

$T(0) = -15$

$-15 = -a - b\cos(0)$

$-15 = -a - b$

$T(12) = 5$

$5 = -a - b\cos(\pi)$

$5 = -a + b$

$a = 5$ ... $b = 10$

Quote:

Find the average temperature for the first 10 hours.

$T_{avg} = \frac{1}{10-0} \int_0^{10} T(h) \, dh$

Quote:

Use the trapezoid Rule with 4 subdivisions to estimate integral from 0 to 8 of T(h)dh.

$\int_0^8 T(h) \, dh \approx 1[T(0) + 2T(2) + 2T(4) + 2T(6) + T(8)]$

Quote:

Find an expression for the rate that the temperature is changing with respect to h

$\frac{d}{dh} \left[-5 -10\cos\left(\frac{\pi h}{12}\right)\right]$