integrate 1/u du my ans = ln(u) +c plse assist
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Originally Posted by Faz integrate 1/u du my ans = ln(u) +c plse assist You're *almost* correct. As Skeeter pointed out, don't forget the absolute value!
$\displaystyle \int \frac{1}{u} \, du = \ln|u| + C$
Originally Posted by Faz integrate 1/u du my ans = ln(u) +c plse assist This is correct $\displaystyle \int \frac{1}{u} du = ln(u) + c $ What exactly is your question? Edit: Aaaaargh, too slow
Originally Posted by Rapha This is correct Mr F says: Not quite. See skeeter's reply. $\displaystyle \int \frac{1}{u} du = ln(u) + c $ What exactly is your question? Edit: Aaaaargh, too slow ..
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