suppose e>0 b>0

so if

|x-a|<b >>> |x-a|<|x|<b

|f(x)-f(a)|<e >>> |f(x)-f(a)|<|f(x)|<e

from that step they do write same things all over again and conclude that.

lim (f(x))=f(a)

x->infinity

how to get from the step i showed to this conclution?

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- Dec 31st 2008, 03:43 PMtransgalacticunderstanding continuety proof..
suppose e>0 b>0

so if

|x-a|<b >>> |x-a|<|x|<b

|f(x)-f(a)|<e >>> |f(x)-f(a)|<|f(x)|<e

from that step they do write same things all over again and conclude that.

lim (f(x))=f(a)

x->infinity

how to get from the step i showed to this conclution? - Dec 31st 2008, 11:49 PMMathstud28
- Jan 2nd 2009, 03:40 PMtransgalactic
i ment that if

|x|<b

then this is definitely true

|x-a|<b - Jan 2nd 2009, 07:27 PMMathstud28