Suppose e^(e^x)=an x^n, prove that an>=e(r ln n)^(-n) when n>1, r is a constant larger than e. Thanks
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Suppose e^(e^x)=an x^n, prove that an>=e(r ln n)^(-n) when n>1, r is a constant larger than e. Thanks
the reason that you haven't got any response is that your question is not very clear. i don't know about other members in here but if a poster didn't bother to explain his/her question clearly, i.e.Quote:
Originally Posted by cyclic
mathematically understandable, then i would just ignore the question. your question may be understood in different ways. for example, this one might be what you meant:
supposefor some
then there exists a real constant
independent from
and
such that
Your understand is correct. I am very sorry that I don't know how to post mathematical formula.
i think we also need to assume thatQuote:
Originally Posted by cyclic
because otherwise it would be possible to choose
which would disprove the problem. for example
has a root in the interval
is a series
wow! that totally changes the problem!! so you mean this:Quote:
Originally Posted by cyclic
I think that the problem should be very difficult, becauce in a Chinese math forum there is no one can solve it
Suppose, prove that
when n>1, r is a constant larger than e.
Note that: NOt there exists a real constant r > e, BUT r is a constant larger than e