Suppose e^(e^x)=an x^n, prove that an>=e(r ln n)^(-n) when n>1, r is a constant larger than e. Thanks

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- December 31st 2008, 04:56 AMcyclicA problem in analysis
Suppose e^(e^x)=an x^n, prove that an>=e(r ln n)^(-n) when n>1, r is a constant larger than e. Thanks

- January 1st 2009, 08:39 PMNonCommAlg
the reason that you haven't got any response is that your question is not very clear. i don't know about other members in here but if a poster didn't bother to explain his/her question clearly, i.e.

mathematically understandable, then i would just ignore the question. your question may be understood in different ways. for example, this one might be what you meant:

suppose for some then there exists a real constant independent from and such that - January 2nd 2009, 03:18 AMcyclicThank you very much.
Your understand is correct. I am very sorry that I don't know how to post mathematical formula.

- January 2nd 2009, 03:33 AMNonCommAlg
- January 2nd 2009, 05:20 AMcyclicYou are wrong
is a series

- January 2nd 2009, 05:30 AMNonCommAlg
- January 2nd 2009, 05:39 AMcyclicYes, that is correct.
I think that the problem should be very difficult, becauce in a Chinese math forum there is no one can solve it

- January 2nd 2009, 05:51 AMcyclicI post the problem again
Suppose , prove that

when n>1, r is a constant larger than e.

*Note that*:**NOt**there exists a real constant r > e,**BUT**r is a constant larger than e