Thread: newton's method

Q1 - Use Newton's method to find the value of x for the function f(x)=2x^2 + 4x - 3 = 0 ; x > 0
Note : Perform only 3 iterations.



Q2 - Evaluate the integral ∫ (1 + sinx)^6 cosxdx by proper substitution.




Q3 - Evaluate the sum ∑ k(k - 2)(k + 2) using the required theorems.


Note on this sign "∑" on the upper side it is 35 and on the lower side it is k-1....I dont know how to use the tags here coz am new...sorry plz...

Help me in this

The exact same questions you posted here has been posted elsewhere and already received a response:
http://www.mathhelpforum.com/math-he...t-hw-help.html

According to Q2

Originally Posted by Angel Rox

Q2 - Evaluate the integral ∫ (1 + sinx)^6 cosxdx by proper substitution.

Substitute z:= sin(x) => z' = cos(x) =>

=>

Yeah I saw that response which u have mentioned but i couldnt understand his performing methodology because he has just given some simple hints...so if any one could simplify it a lil bit...I'll be thankful...

Originally Posted by Angel Rox

Yeah I saw that response which u have mentioned but i couldnt understand his performing methodology because he has just given some simple hints...so if any one could simplify it a lil bit...I'll be thankful...

What parts of it you did not understand?

I think i can do Q2 by substituting 1+ sinx = u

But in Q 1 which approximation we should take next?

and in Q3 he wrote we need to expand to get and then sum these two terms seperately... How we r going to do this??

Q1. Try as Grandad mentioned to find , then use to find ,...,then use to find

Q3. The lower side should read k=1.

And what Grandad meant is that once you have expanded it to:


Separate it into:

Recall that:

Originally Posted by Angel Rox

I think i can do Q2 by substituting 1+ sinx = u

But in Q 1 which approximation we should take next?

and in Q3 he wrote we need to expand to get and then sum these two terms seperately... How we r going to do this??

And thank Grandad as well. His post was sufficient for your question and my reply was based on it.

Ok I have thanked him too...Thanx to all of u ...