Can any1 help me to find the solution for this problem
lim a sin square x b log cosx /4
x->0
equals to half i.e 1/2
Find a and b.
Hello Arvind,Originally Posted by For Arvind by Chris
Can you recheck the question? Something is not right here...
Why would they keep constants like that (a and b) when they can group it and call it one constant ( like c = ab) ?
And secondly, a simple L'Hospital will show that:
$\displaystyle \lim_{x\to0}\sin^2 x\cdot \log\left(\cos x\right) = 0$
So I dont think a constant ab exists
All this leads me to believe there is a typo