Can any1 help me to find the solution for this problem

lim a sin square x b log cosx /4

x->0

equals to half i.e 1/2

Find a and b.

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- Dec 27th 2008, 08:54 PMarvindshetty86Limit problem.
Can any1 help me to find the solution for this problem

lim a sin square x b log cosx /4

x->0

equals to half i.e 1/2

Find a and b. - Dec 27th 2008, 08:59 PMChris L T521
- Dec 27th 2008, 08:59 PMkalagota
- Dec 27th 2008, 09:12 PMarvindshetty86
yes Chris that's the question.Thanks for the help.

- Dec 27th 2008, 10:50 PMIsomorphismL'HospitalsQuote:

Originally Posted by**For Arvind by Chris**

Can you recheck the question? Something is not right here...

Why would they keep constants like that (a and b) when they can group it and call it one constant ( like c = ab) ?

And secondly, a simple L'Hospital will show that:

$\displaystyle \lim_{x\to0}\sin^2 x\cdot \log\left(\cos x\right) = 0$

So I dont think a constant ab exists (Thinking)

All this leads me to believe there is a typo (Nod)