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Math Help - Bernoulli equation particular

  1. #1
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    Angry Bernoulli equation particular

    Anyone can help me with this equation


    dy/dx*(x^2*y^3+xy)=1

    Thx

    PS: I doubt that is a Bernoulli equation ?????
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  2. #2
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    Quote Originally Posted by tenca View Post
    Anyone can help me with this equation


    dy/dx*(x^2*y^3+xy)=1

    Thx

    PS: I doubt that is a Bernoulli equation ?????
    Actually it is! If we write the ODE as

     \frac{dy}{dx} = \frac{1}{x^2 y^3+xy}

    Then flip the equation

     \frac{dx}{dy} = x^2 y^3+xy

    and think of this as an equation for  x = x(y)

    make the substitution  x = \frac{1}{u} and it will become linear.
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