hallo all, I have the following problem: Sorry, made an error and typed the wrong one. x^(-2 ). e^x dx is the one I mean. Is it even possible to solve this?
Last edited by Coele; December 23rd 2008 at 01:07 PM. Reason: made an error
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Originally Posted by Coele hallo all, I have the following problem: òx-2·ex dx = ? Is it even possible to solve this? Sure. But let's begin by converting that symbol to the more familiar : As written, the integral is simply performed: But I suspect that you actually mean this: For such an integral, we break it up into two portions: And hopefully you can take it from there.
sorry, my bad, I made an error: I ment this one: e^x / x^2 dx (or as I wrote it before: x^-2 . e^x dx
Originally Posted by Coele sorry, my bad, I made an error: I ment this one: e^x / x^2 dx (or as I wrote it before: x^-2 . e^x dx I don't think this has an elementary, closed form antiderivative. you could use the infinite series for , divide by , and integrate term for term.
That is correct, it has no nice indefinite form. We can write it in terms of the Exponential Integral, though. Ei is the notation for the Exponential Integral.
I see thanks a lot guys.
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