For the first integral, try a substitution y = x + 1. Then write the integral as:

Int(y^{-1/2}dy)

The second integral works with a similar substitution.

For the third consider a trig substitution: x = 3*tan(y). then the denominator of the integrand becomes:

sqrt(9 + 9*[tan(y)]^2) = 3*sqrt(1 + [tan(y)}^2) = 3*sec(y)

-Dan