find the limit

**varunnayudu** · December 22nd 2008, 08:39 PM

$\lim_{n \to \infty} \frac{3n}{2(n+1)}$

**Chris L T521** · December 22nd 2008, 08:42 PM

Originally Posted by varunnayudu

$\lim_{n \to \infty} \frac{3n}{2(n+1)}$

Multiply both numerator by $\frac{1}{n}$ to get $\lim_{n\to\infty}\frac{3}{2\left(1+\frac{1}{n}\rig ht)}=\dots$

**kalagota** · December 22nd 2008, 08:46 PM

Originally Posted by varunnayudu

$\lim_{n \to \infty} \frac{3n}{2(n+1)}$

using partial fraction: $\lim_{n \to \infty} \frac{3n}{2(n+1)} = \lim_{n \to \infty}\left(\dfrac{3}{2} - \dfrac{3}{2(n+1)}\right) = \dfrac{3}{2}$

in fact, since the numerator and the denominator are of the same degree, just take their respective leading coefficient..

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