# Math Help - help me please with integration

1. ## help me please with integration

calculate the lenght (L) from point M(0;-1) to point N(1;2) given y=3(x^2)-1

2. Originally Posted by Tommy
calculate the lenght (L) from point M(0;-1) to point N(1;2) given y=3(x^2)-1
The arclength? The formula for arclength is $\int_a^b\sqrt{1+f'(x)^2}dx$

So here $a=1,b=2,f'(x)=6x$