calculate the lenght (L) from point M(0;-1) to point N(1;2) given y=3(x^2)-1
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Originally Posted by Tommy calculate the lenght (L) from point M(0;-1) to point N(1;2) given y=3(x^2)-1 The arclength? The formula for arclength is $\displaystyle \int_a^b\sqrt{1+f'(x)^2}dx$ So here $\displaystyle a=1,b=2,f'(x)=6x$
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