1. ## Word Problem

The area bounded by the parabola y=x^2 and the lines y=1 and y=9 equals?

what are you suppose to do?

2. It is hoped that you have just the tiniest introduction to integral calculus. Do you? Without it, you cannot solve it exactly.

You should also recognize and exploit symmetries. Can you? Without this, you will become confused.

Note: What makes this a "Word" problem?

3. Originally Posted by TKHunny
It is hoped that you have just the tiniest introduction to integral calculus. Do you? Without it, you cannot solve it exactly.

You should also recognize and exploit symmetries. Can you? Without this, you will become confused.

Note: What makes this a "Word" problem?
I have, I tried using LRAM, and RRAM to do the problem, but there is no end point, how do you know when to stop?

4. I, unfortunately, have no idea what "LRAM" and "RRAM" are.

I would, however, do this as $\int_1^9 x dy$.

5. Originally Posted by Seigi
The area bounded by the parabola y=x^2 and the lines y=1 and y=9 equals?

what are you suppose to do?
The first thing you're supposed to do is draw a diagram.

Originally Posted by Seigi
I have, I tried using LRAM, and RRAM to do the problem, but there is no end point, how do you know when to stop?
*Ahem* Note that the lines y = 1 and y = 9 intersect the parabola at (1, 1), (-1, 1), (3, 9) and (-3, 9). I too have no idea what LRAM and RRAM mean but there are endpoints. Perhaps LRAM means Left Rectangle Approximation Method etc. But if so, why would you use these approximations ..... ? Anyway, using calculus there are now a number of approaches available to solving the problem. The use of symmetry suggested by TKH is a very useful suggestion.

Then you can divide the required region to the right of the y-axis into two parts. One of these parts is a rectangle. The other part is simply the area between the line y = 9 and the curve y = x^2 ......

6. Originally Posted by HallsofIvy
I, unfortunately, have no idea what "LRAM" and "RRAM" are.

I would, however, do this as $\int_1^9 x dy$.
I'm not sure that this integral will help ....