1. ## innequality prove question..

the question and how i tried to solve it are in this link

http://img155.imageshack.us/img155/4710/55108660qi1.gif

2. $\sin{x}$ as an infinite series ...

$\sin{x} = x - \frac{x^3}{3!} + \frac{x^5}{5!} - \frac{x^7}{7!} + \, ...$

3. Originally Posted by skeeter
$\sin{x}$ as an infinite series ...

$\sin{x} = x - \frac{x^3}{3!} + \frac{x^5}{5!} - \frac{x^7}{7!} + \, ...$
so the solution is just picking the tailor series of sin(x) wich developed enough to fit this inequality?