the question and how i tried to solve it are in this link http://img155.imageshack.us/img155/4710/55108660qi1.gif
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$\displaystyle \sin{x}$ as an infinite series ... $\displaystyle \sin{x} = x - \frac{x^3}{3!} + \frac{x^5}{5!} - \frac{x^7}{7!} + \, ...$
Originally Posted by skeeter $\displaystyle \sin{x}$ as an infinite series ... $\displaystyle \sin{x} = x - \frac{x^3}{3!} + \frac{x^5}{5!} - \frac{x^7}{7!} + \, ...$ so the solution is just picking the tailor series of sin(x) wich developed enough to fit this inequality?
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