Hi
Newton's law is
where is the temperature of the surroundings and the initial temperature of the body
Let be the temperature at
and the temperature at
Then
Dividing the 2 expressions
hey everyone.
i hve a doubt in dis question: A body at temperature T higher than its surroundings cools down according to the formula T=(T-T(with base 0))e(raise to the power of -kt), (newton's law of cooling) where T(with base 0) is the temperature of the surroundings, t is the time in hours, and k is a constant. It is found that the temperature of the body falls from 80degrees celsius to 60 degrees celsius in 2 hours. If T(with base 0)=20 degress celsius, how long does it take for the temperature of the body to fall to 30 degrees celsius?....well is the answer coming out to be 8 hrs 50 mins...i just wana confirm...
thankx for seeing dis qs....hope 2 c a reply soon...
tc pple