I've been working with decomp. for: [(ln(x))^(-s)]/(x(x-1)) And I get: [(ln(1))^(-s)]/(x-1) - [(ln(0))^(-s)]/x I know ln(1) is zero and that ln(0) is negative infinity (or complex depending on who you are), but is this still a correct solution?
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Originally Posted by rman144 I've been working with decomp. for: [(ln(x))^(-s)]/(x(x-1)) And I get: [(ln(1))^(-s)]/(x-1) - [(ln(0))^(-s)]/x I know ln(1) is zero and that ln(0) is negative infinity (or complex depending on who you are), but is this still a correct solution? Hi [(ln(x))^(-s)]/(x(x-1)) = [(ln(x))^(-s)]/(x-1) - [(ln(x))^(-s)]/x
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