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Thread: dy/dx

  1. December 18th 2008, 08:28 AM #1
    Emmeyh15@hotmail.com
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    dy/dx

    For each function, find dy/dx. Show Work.

    y=sinx(squared)+sin(squared)x
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  2. December 18th 2008, 08:34 AM #2
    nrslmz
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    The derivative of: sin(x^2)+sin^2(x)
    according to the chain rule,
    cos (x^2)*2x + 2sinx*cosx
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