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Math Help - HELP!

  1. #1
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    HELP!

    Use 1' Hopital's Rule t find the limit. SHOW WORK Lim cos x-1 /2x(squared) is 0/0 form.
    Last edited by Emmeyh15@hotmail.com; December 18th 2008 at 09:24 AM.
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  2. #2
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    Quote Originally Posted by Emmeyh15@hotmail.com View Post
    Use 1' Hopital's Rule t find the limit. SHOW WORK Lim cos x-1 /2x(square root 2) is 0/0 form.

    Hi there,

    Whenever you have a limit of indeterminate form of type 0/0
    just differentiate the top and the bottom separately.


    <br />
\frac{d}{dx}(Cos(x)-1)= -Sin(x)<br />

    <br />
\frac{d}{dx}(2x\sqrt{2})=\sqrt{2}\frac{d}{dx}(2x)=  2 \sqrt{2}<br />

    Now you take the limit of f'(x)/g'(x)

    <br />
\lim_{x \rightarrow 0}\frac{-sin(x)}{2\sqrt{2}}=0<br />

    NOTE: Here we differentiated only once, but sometimes you have to differentiate multiple times in order to get the limit.
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  3. #3
    Grand Panjandrum
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    Quote Originally Posted by fonso_gfx View Post
    Hi there,

    Whenever you have a limit of indeterminate form of type 0/0
    just differentiate the top and the bottom separately.


    <br />
\frac{d}{dx}(Cos(x)-1)= -Sin(x)<br />

    <br />
\frac{d}{dx}(2x\sqrt{2})=\sqrt{2}\frac{d}{dx}(2x)=  2 \sqrt{2}<br />

    Now you take the limit of f'(x)/g'(x)

    <br />
\lim_{x \rightarrow 0}\frac{-sin(x)}{2\sqrt{2}}=0<br />

    NOTE: Here we differentiated only once, but sometimes you have to differentiate multiple times in order to get the limit.
    you can use \sin(x) and \cos(x) for the trig functions to get \sin(x) \cos(x) in LaTeX

    CB
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