Ok, so i have the eq

d^2x/dt^2 + 4x = sin2t

And have to first find the auxiliary eq (AE) and also the particular soln.

then obtain the general soln and confirm that no periodic soln exists.

So far i have found the AE to be m^2 + 4 = 0,

Which gives the solution Aexp(2jt) + Bexp(-2jt) [where j = -1^0.5]

Ive then attempted to use a trial solution of the form t^2(asin2t +bcos2t)

ive differentiated this twice and substituted into the initial equation,

However this is where i get in a muddle, when i substitute the two terms in and simplify, then by equating like terms i get that for the particular soln:

(8at +2b)cos2t = 0 and (2a-8bt)sin2t = sin2t

And i cannot see how to find a and b from here, yet nor can i see where i have gone wrong, as when i tried using t(asin2t + bcos2t) as the trial solution then i ended up with a=b=0