Hi guys, doing this on spread sheets ~ exel.

Using newtons-Raphson method of succesive approximation to determine to 4 decimal places the root of equation 0.25x^2-6sin2x =0 in the region of x = 4.2

If f(x) = 0.25^2-6sin2x

Whats would f'(x) be???

I think maybe f'(x) = 0.50x + 12cos2x ???