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Math Help - Flux Integral

  1. #1
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    Flux Integral

    Let S be the part of the plane Find the flux of the vector field across the surface S.
    I'm stuck
    If i use the equation int int Fnds i get the int int of 11/(11)^(1/2)
    if I use int int Fn |ruXrv|i get stuck at ruXrv because I don't know how to find my ru and rv.
    I can't use the divergence therem because there are no values.

    What method should I use? And how do I set up the bounds? Thank you so much!
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  2. #2
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    (1,3,1)*(2,1,1)/(2*2+1+1)^(1/2)=6/6^(1/2)
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  3. #3
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    how do you come up with that?
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  4. #4
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    Sorry for my English is not very well.

    The direction of the flux vector is A=(1,3,1),and the direction of the normal of the plane is B=(2,1,1).So the flux of the vector field across the surface need to calculate the flux vector project on the normal of the plane.The angle x formed by two vector A and B is calculated by

    cosx=A*B/(׀A׀*׀B׀)

    so the angle x between the vector (1,3,1) and (2,1,1) is

    cosx=6/66^(1/2)

    so the length of the projection on the the plane's normal of the flux vector is

    L=׀A׀*cosx=11^(1/2)*6/66^(1/2)=6/6^(1/2)

    its direction as same as (2,1,1).
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