# Math Help - curves

1. ## curves

show that the curves 3x^2+2x-3y^2=1 and 6xy+2y=0 are orthogonal (i.e. there slopes everywhere are perpendicular)
thank you, your help is very appreciated!

2. If you take the derivatives of both curves wrt x then the derivative of the first curve is (3x+1)/(3y) and the derivative of the second curve wrt x is
(-3y)/(3x+1). So the slopes are opposite reciprocals. This means they are perpendicular. Hope this helps, someone else will hopefully explain it better.

3. im sorry i had a typo. the first equation i forgot to put = 1, i dont know if that changes anything at all or not..

4. nope because the derivative of a constant is still zero

5. thank you!