Use a(t) = -32 feet per second squared as the acceleration due to gravity. A ball is thrown vertically upward from the ground with an initial velocity of 96 feet per second. How high will the ball go?
Follow Math Help Forum on Facebook and Google+
You can use the equation of motion: $\displaystyle v^2=u^2+2as $ Where: v=final velocity (0) u=initial velocity ($\displaystyle 96\text{fts}^{-1}$) a=acceleration ($\displaystyle -32\text{fts}^{-2}$) s=displacement (height)
View Tag Cloud