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Math Help - inflection

  1. #1
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    inflection

    Let
    f(x) = (x + 1)^2(x-2).
    (a) Find the maximum and minimum values of
    f(x);
    (b) A point of inflection is a point where the graph changes direction of
    concavity, i.e. a point where
    f''(x) = 0. Find the inection point(s) of

    f, and determine where the function is concave up and concave down
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  2. #2
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    What problems are you having? What's your working so far?
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  3. #3
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    how to go about

    first i let x=0
    i got f(x)=-2 , this is the turning point?
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  4. #4
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    Quote Originally Posted by mathseek View Post
    first i let x=0
    i got f(x)=-2 , this is the turning point?
    The maxima/minima of a curve is given by the point when it's gradient is zero. The gradient of a curve is given by the first derivative of the function the describes it.

    In other words:

     m = f'(x) = 0

    So, find f'(x), set it equal to zero, and solve for x. This will give you the x co-ordinates of the maxima/minima. THEN plug that value back into the original equation, f(x), to find the y value. (y=f(x)).
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