(secx)^2 sqrt((tanx)^3)dx

x^3/sqrt(x^2+25)

$\displaystyle (5x^2 + 6x - 12)/{{x^4}}$

Integral from 3 to sqrt(24) of x/sqrt(x^2-8)

Integral from 1/2 to 5/2 of 1/sqrt(6x+1)

I don't get any of this.. I have a test of this Tuesday and still have no idea how to do it..