Help me , please!

**butbi9x** · December 14th 2008, 04:06 PM

Evaluate the indefinite. Illustrate, and check that your answer is reasonalbe, by graphing both the function and its antiderivative.

$\int (2x+3)e^{x}dx$

I can't do it

**chabmgph** · December 14th 2008, 04:13 PM

Originally Posted by butbi9x

Evaluate the indefinite. Illustrate, and check that your answer is reasonalbe, by graphing both the function and its antiderivative.

$\int (2x+3)e^{x}dx$

I can't do it

Hi butbi9x,

You may want to try solving it by parts. (Say let $u = 2x+3$ and $dv = e^xdx$ )

**mech.engineer.major** · December 14th 2008, 04:18 PM

You can try using the Product Rule with the quantities (2x+3) and e^x.

**mr fantastic** · December 14th 2008, 04:50 PM

Originally Posted by mech.engineer.major

You can try using the Product Rule with the quantities (2x+3) and e^x.

This would be a good suggestion if the question was asking to find the derivative. However, the question asks for the anti-derivative.

**butbi9x** · December 14th 2008, 04:59 PM

"Illustrate, and check that your answer is reasonalbe, by graphing both the function and its antiderivative." --> I don't understand it , Check that my answer is reaonable by graphing ???

**mech.engineer.major** · December 14th 2008, 05:00 PM

Oh I'm sorry I must have misread the question. You're absolutely right, thank you for pointing that out mr. fantastic. My apologies if I caused any confusion butbi9x.

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