# Diverge/Converge

• December 14th 2008, 01:43 PM
Diverge/Converge
Back again, was going through some exams and wanted to make sure I was doing this right.. last day to study, final tomorrow at 10 PM PST

Quote:

Determine whether the series converges or diverges. Justify your work by citing the appropriate test.

Summation from k=1 to infinite of $(arctan k)/k^2$

Can't I just use the p-series and p>2 and it converges?

Or do I have to use a comparison, arctan is (-pi/2,pi/2) correct?
• December 14th 2008, 01:48 PM
Plato
Just note that $\frac{{\arctan (k)}}
{{k^2 }} < \frac{{\pi /2}}
{{k^2 }}$
.
• December 14th 2008, 01:55 PM