Linear interpolation

**Haris** · December 13th 2008, 09:04 AM

I dont know what linear inteprolation is. Could someone explain how to solve this problem please. Cheers.

**skeeter** · December 13th 2008, 09:49 AM

ahh ... makes me reminisce about the old days when linear interpolation was used every day using tables in CRC manuals.

linear interpolation uses a model of a linear rate of change (slope) between two successive values in the table to find an unknown value between those two values.

$\frac{0.8667 - 0.8593}{1.18 - 1.16} = \frac{0.8667 - x}{1.18 - 1.175}$

$\frac{.0077}{.02} = \frac{0.8667 - x}{.005}$

$0.8667 - x = \frac{(.0077) \cdot (.005)}{.02}$

$x = 0.8667 - \frac{(.0077) \cdot (.005)}{.02}$

$x \approx 0.8648$

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