I'm a little stumped the equation is x sqrt (1-x^4) using substitution. Thanks sososososo much in advance.
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x^2=sin(y) is a good substitution dx=1/2 cos(y)/sin^.5(y) dy sqrt(1-x^4)=cos(y) you will be integrating 1/2 cos^2(y) dy
Originally Posted by samer_guirguis_2000 x^2=sin(y) is a good substitution dx=1/2 cos(y)/sin^.5(y) dy Mr F remarks: is sufficient - there's no need to express x in terms of y. sqrt(1-x^4)=cos(y) you will be integrating 1/2 cos^2(y) dy ..
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