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Math Help - MAXIMUM PROFIT (multiple variables)

  1. #1
    Newbie Audriella's Avatar
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    MAXIMUM PROFIT (multiple variables)

    Sadly i do have one more i thought the last question would make more sense of this one unfortunately it did not...

    So if you could be so kind here it is...

    It costs you c dollars each to manufacture and distribute backpacks. If the backpacks sell at x dollars each, the number sold given by
    n=(a/(x-c))+(b(100-x))
    where a and b are certain positive constants.
    what selling price will bring a maximum profit?



    in my notes to find the max profit one would have to have two seperate functions find their derivatives and have them = to each other... like in my last question.
    The issue here is that there is only one function.
    also what is supposed to be the marginal revenue

    i am sorry if this is obvious and i am just not missing it.. but something does not seem to add up to me.


    thank you so very much...again
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  2. #2
    Flow Master
    mr fantastic's Avatar
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    Quote Originally Posted by Audriella View Post
    Sadly i do have one more i thought the last question would make more sense of this one unfortunately it did not...

    So if you could be so kind here it is...

    It costs you c dollars each to manufacture and distribute backpacks. If the backpacks sell at x dollars each, the number sold given by
    n=(a/(x-c))+(b(100-x))
    where a and b are certain positive constants.
    what selling price will bring a maximum profit?



    in my notes to find the max profit one would have to have two seperate functions find their derivatives and have them = to each other... like in my last question.
    The issue here is that there is only one function.
    also what is supposed to be the marginal revenue

    i am sorry if this is obvious and i am just not missing it.. but something does not seem to add up to me.


    thank you so very much...again
    P = nc - nx = n(c - x).

    Substitute for n and solve dP/dx = 0. Test the nature of all solutions - you want the minimum.
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