1) ∫(7x^(3) - 4x^(2) +9x -10)dx
2) ∫ [(6 √(x)+2)/ √(x)]
3) ∫6x^(7) +4 / (x)
Thanks
Use the formula $\displaystyle \int x^a dx = \frac{1}{a + 1}x^{a+1}+C$.
$\displaystyle \int{6 + 2x^{-\frac{1}{2}}\,dx} = \int{6x^0 + 2x^{-\frac{1}{2}}\,dx}$
$\displaystyle = \frac{6}{1}x^1 + \frac{2}{\frac{1}{2}}x^{\frac{1}{2}} + C$
$\displaystyle = 6x + 4x^{\frac{1}{2}} + C$
$\displaystyle = 6x + 4\sqrt{x} +C$.