Find the area between y=ln(x) and the x axis on the interval [1,e^2]

I know how to integration, but is this possible? How would I integrate lnx?

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- December 11th 2008, 04:46 PMSm10389Basic Integration
Find the area between y=ln(x) and the x axis on the interval [1,e^2]

I know how to integration, but is this possible? How would I integrate lnx? - December 11th 2008, 05:02 PMJhevon
- December 11th 2008, 05:07 PMSm10389
Ok so use 1 and lnx.

My answer is xlnx-1

is that right? - December 11th 2008, 05:08 PMJhevon
- December 11th 2008, 05:11 PMSm10389
maybe i just wrote it wrong

u=ln(x)

v'=1

u'=1/x

v= x

=

lnx*x - x(1/x)

=

(lnx) - 1

Where is it wrong - December 11th 2008, 05:12 PMJhevon
- December 11th 2008, 05:13 PMSm10389
that is integrating... by parts.